A mass of `6 kg ` is supended by a rope of length `2 m `from the ceiling. A force of` 50 N` in the horizontal direction is applied at the midpoint ` P` of the rope a shown. What is the angle, the rope makes with the vertical in equilibrium? Take `g= 10ms^(-2)`.Neglect the mass of the rope.

Options

A. A)`50^(@)`
B. B)`60^(@)`
C. C)`30^(@)`
D. `40^(@)`

Answer

D

Explanation

`tantheta=(50)/(6g)=0.83`

or `tantheta=tan40^(@)ortheta=40^(@)`