If the angle of minimum deviation is `60^(@)` for an equilateral prism , then the refractive index of the material of the prism is

Options

A. A)1.41
B. B)1.5
C. C)`1.6`
D. D)`1.73`

Explanation

`mu=(sin((A+delta_(m))/(2)))/("sin"(A)/(2))`
For equilateral prism , `angleA=60^(@)`
`thereforemu=(sin((60^(@)+60^(@))/(2)))/("sin"((60^(@))/(2)))=(sin60^(@))/(sin30^(@))=((sqrt(3))/(2))/((1)/(2))`
`=sqrt(3)=1.73`