The current I through `10Omega` resistor in the circuit given below is

Options

A. A)50 mA
B. B)20 mA
C. C)40 mA
D. D)80mA

Answer

D

Explanation

Here ,diode `D_(2)` is reverse biased while `D_(1)` is forward biased . So , no current flows across `D_(2)` , current flows throught diode `D_(1)` .
`I=(V)/(R)=(2)/(10+15)=(2)/(25)=0.08A=80mA`