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The resonance frequency of the tank cir...

The resonance frequency of the tank circuit of an oscillator when `L=(10)/(pi^(2))mHandC=0.04muF` are connected in parallel is

A

A)250 kHz

B

B)25 kHz

C

C)2.5 kHz

D

D)25 MHz

Text Solution

Verified by Experts

The correct Answer is:
B
In parallel resonant circuit resonance frequency
`f_(0)=(1)/(2pisqrt(LC))(1)/(2pisqrt((10xx10^(-3))/(pi^(2))xx0.04xx10^(-6)))`
`=(10^(4))/(2xx0.2)=25kHz`
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