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If the volume of a block of aluminium...

If the volume of a block of aluminium is decreased by `1%` , the pressure (stress) on its surface is increased by (Bulk) modulus of `Al=7.5xx10^(10)Nm^(-2))`

A

`7.5xx10^(10)Nm^(-2)`

B

`7.5xx10^(8)Nm^(-2)`

C

`7.5xx10^(6)Nm^(-2)`

D

`7.5xx10^(4)Nm^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Given modulus ,
`B=(p)/(DeltaV//V)=(pV)/(DeltaV)`
or `p=(BDeltaV)/(V)=7.5xx10^(10)xx(1)/(100)`
`=7.5xx10^(8)Nm^(-2)`
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