The excess pressure inside one soap bubble is three times that inside a second soap bubble , then the ratio of their surface areas is

Options

A. A)`1:9`
B. B)`1:3`
C. C)`3:1`
D. D)`1:27`

Answer

A

Explanation

Accordingly
`(4T)/(r_(1))=3xx(4T)/(r_(2))`
`rArr(r_(1))/(r_(2))=(1)/(3)`
Ratio of surface areas
`(A_(1))/(A_(2))=(4pir_(1)^(2))/(4pir_(2)^(2))=(1)/(9)`