The period of a simple pendulum inside a stationary lift is T. The lift accelerates upwards with an acceleration of g/3. the time period of pendulum will be

Options

A. A)`sqrt(2)T`
B. B)`(T)/(sqrt(2))`
C. C)`(sqrt(3))/(2)T`
D. D)`(T)/(3)`

Answer

C

Explanation

When lift accelerates upwards , then effective acceleration on the pendulum
`g_(eff)=g+(g)/(3)=(4g)/(3)`
`therefore` Time period `T.=2pisqrt((l)/(g_(eff)))=2pisqrt((l)/(4g//3))`
`=(sqrt(3))/(2)*2pisqrt((l)/(g))`
`=(sqrt(3))/(2)T`