Two particles of equal charges after being accelerated through the same potential difference enter a uniform transverse magnetic field and describe circular path of radii `R_(1)andR_(2)` respectively . Then the ratio of their masses `(M_(1)//M_(2))` is

Options

A. `(R_(1))/(R_(2))`
B. `((R_(1))/(R_(2)))^(2)`
C. `(R_(2))/(R_(1))`
D. `((R_(2))/(R_(1)))^(2)`

Answer

B

Explanation

Radius of circular path
`R=(mv)/(qB)`
but `mv=sqrt(2mqV)`
`thereforeR=(sqrt(2mqV))/(qB)or Rpropsqrt(m)`
or `(R_(1)^(2))/(R_(@)^(2))=(M_(1))/(M_(2))or(M_(1))/(M_(2))=(R_(1)^(2))/(R_(2)^(2))=(R_(1)/(R_(2)))^(2)`