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The flux linked with a circuit is giv...

The flux linked with a circuit is given by `phi=t^(3)+3t-7`. The graph between time (x-axis) and induced emf (y-axis)will be a

A

straight line through the origin

B

straight line with positive intercept

C

straight line with negative intercept

D

parabola not through the origin

Text Solution

Verified by Experts

`phi=t^(3)+3t-7`
`therefore` Induced emf
`e=(dphi)/(dt)=-(3t^(2)+3)=-3t^(2)-3`
Att = 0 , e =- 3V
Therefore , shape of graph will be a parabola not through origin .
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