A resistor `30Omega` , inductor of reactance `10Omega` and capacitor of reactance `10Omega` are connected in series to an AC voltage source `e=300sqrt(2)sin(omegat)`. The current in the circuit is

Options

A. a)`10sqrt(2)A`
B. b)`10 A`
C. c)`30sqrt(11)A`
D. d)`30//sqrt(11)A`

Answer

B

Explanation

`e=300sqrt(2)sinomegat`
`I_(0)=(e_(0))/(Z)=(300sqrt(2))/(sqrt((30)^(2))+(10-10)^(2)) " " { becauseZ=sqrtR^(2)+(X_(L)-X_(C))^(2)}`
`=(300sqrt(2))/(30)=10sqrt(2)A` ,br> `therefore` Current `I=(I_(0))/(sqrt(2))=10A`