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The excess pressure inside a spherical d...

The excess pressure inside a spherical drop of water is four times that of another drop. Then their respective mass ratio is

A

a)`1:16`

B

b)`8:1`

C

c)`1:4`

D

d)`1:64`

Text Solution

Verified by Experts

The correct Answer is:
D
Excess pressure inside a spherical drop of water
`P=(2T)/R`
Given: `p_1=4p_2`
`(2T)/R_1=4 times (2T)/R_2`
or `R_2=4R_1`
Now, `m_1/m_2= (4 pi R_1^3 d_1)/(4 pi R_2^3 d_2)`
or `m_1/m_2=R_1^3`
or `m_1/m_2=1/64`
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