In a carnot engine, the temperature of reservoir is `927^@C` and that of sink is `27^@C`. IF the word done by the engine when it transfers heat from reservoir to sink is `12.6 times 10^6 J`, the quantity of heat absorbed by the engine from the reservoir is

Options

A. a)`16.8 times 10^6 J `
B. b)`4 times 10^6J`
C. c)`7.6 times 10^6 J `
D. d)`4.25 times 10^6 J`

Answer

A

Explanation

`Q/W=T_1/T_2`
`therefore Q/(12.6 times 10^6)=(927+273)/(27+273)`
or `Q=16.8 times 10^6 J`