A bus begins to move with an acceleration of 1 `ms^(-2)`. A man who is 48 m behind the bus starts running at 10 `ms^(-1)` to catch the bus. The man will be able to catch the bus after

Options

A. 6s
B. 5s
C. 3s
D. 8s

Answer

D

Explanation

Given a = 1 `ms^(-2)`, s = 48 m
By the equation of motion
`48 + (1)/(2) at^(2) = 10t`
t = 8s