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A particle is moving with constant accel...

A particle is moving with constant acceleration from A to B in a straight line AB. If u and v are the velocities at A and B respectively then its velocity at the midpoint C will be

A

`((u^(2) + v^(2))/(2u))^(2)`

B

`(u + v)/(2)`

C

`(v - u)/(2)`

D

`sqrt((u^(2) + v^(2))/(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
We have standard result for this type of velocity `= sqrt((u^(2) + v^(2))/(2))`
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