A stationary bomb explodes into three pieces. One piece of 2 kg mass moves with a velocity of 8 `ms^(-1)` at right angles to the other piece of mass 1 kg moving with a velocity of 12 `ms^(-1)`. If the mass of the third piece of 0.5 kg, then its velocity is

Options

A. 10 `ms^(-1)`
B. 20 `ms^(-1)`
C. 30 `ms^(-1)`
D. 40 `ms^(-1)`

Answer

D

Explanation

Momentum of third piece

`p = sqrt(p_(x)^(2) + p_(y)^(2))`
`= sqrt((16)^(2) + (12)^(2))`
= 20
`v = (p)/(m) = (20)/(0.5)`
`= 40 ms^(-1)`