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A carnot engine whose efficiency is 40%,...

A carnot engine whose efficiency is 40%, receives heat at 500 K. If the efficiency is to be 50%, the source temperature for the same exhaust temperature is

A

900 K

B

600 K

C

700 K

D

800 K

Text Solution

Verified by Experts

The correct Answer is:
B
Carnot efficiency relation
`eta = (T_(1)-T_(2))/(T_(1))`
Case I `(T_(1)-T_(2))/(T_(1) = 0.4`
`T_(1) - T_(2) = 0.4 T_(1)`
`T_(2) = 0.6 T_(1)`
Case II `(T._(1) - T_(2))/(T._(1)) = 0.5`
`T._(1) = (0.6)/(0.5) T_(1) = 600 K`
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