If two springs A and B with spring constant 2k and k, are stretched separately by same suspended weight, then the ratio between the work done in stretching A and B is

Options

A. `1 : 2`
B. `1 : 4`
C. `1 : 3`
D. `4 : 1`

Answer

A

Explanation

`mg = 2kx_(A)`
`mg = Kx_(B)`
`(x_(A))/(x_(B)) = (1)/(2)`
W = Fx
So, `(W_(A))/(W_(B)) = (Fx_(A))/(Fx_(B)) = (1)/(2)`