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If 2 A of current is passed through CuSO...

If 2 A of current is passed through `CuSO_(4)` solution for 32 s, then the number of copper ions deposited at the cathode will be

A

`4 xx 10^(20)`

B

`2 xx 10^(20)`

C

`4 xx 10^(19)`

D

`2 xx 10^(19)`

Text Solution

Verified by Experts

The correct Answer is:
B
`q = it = n xx 2e`
`n = (it)/(2e) = (2 xx 32)/(2 xx 1.6 xx 10^(-19)) = 2 xx 10^(20)`
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