In a potentiometer experiment, when three cells A, B and C are connected in series the balancing length is found to be 740 cm. If A and B are connected in series balancing length is 440 cm and for B and C connected in series that is 540 cm. Then the emf of `E_(A), E_(B) and E_(C)` are respectively. (in volts)

Options

A. 1, 1.2 and 1.5
B. 1, 2 and 3
C. 1.5, 2 and 3
D. 1.5, 2.5 and 3.5

Answer

A

Explanation

`V_(A) + V_(B) + V_(C) prop 740`
`V_(A) + V_(B) prop 440`
`V_(B) + V_(C) prop 540`
Hence, `V_(A) : V_(B) : V_(C) = 1 : 1.2 : 1.5`