If `E = 100 sin (100 t)` volt and `I = 100 sin(100t + (pi)/(3))`mA are the instantaneous values of voltage and current, then the rms values of voltage and current are respectively

Options

A. 70.7 V, 70.7 mA
B. 70.7 V, 70.7 A
C. 141.4 V 141.4 mA
D. 141.4 V, 141.4 A

Answer

A

Explanation

Given, E = 100 sin 100 t
`I = 100 sin (100 t + (pi)/(3))`
We knows
`E_(rms) = (E_(0))/(sqrt(2))and I_(rms) = (I_(0))/(sqrt(2))`
Hence, `E_(rms) = (100)/(sqrt(2)) = 70.7 V`
`I_(rms) = (100)/(sqrt(2)) = 70.7 mA`