If `E_(0)` is the peak emf, `I_(0)` is the peak current and `phi` is the phase difference between them, then the average power dissipation in the circuit is

Options

A. `(1)/(2)E_(0)I_(0)`
B. `(E_(0)I_(0))/(sqrt(2))`
C. `(1)/(2)E_(0)I_(0) sin phi`
D. `(1)/(2) E_(0)I_(0) cos phi`

Answer

D

Explanation

By the definition we having standard result for this case average power dissipation in the circuit is `(1)/(2) E_(0)I_(0) cos phi`.