The electric field of an electromagnetic wave travelling through vacuum is given by the equation E = `E_(0) sin (kx - omega t)`. The quantity that is independent of wavelength is

Options

A. `(k)/(omega)`
B. `k omega`
C. `omega`
D. k

Answer

A

Explanation

Given, `E = E_(0) sin (kx - omega t)`
Comparing with standard equation, we get
`(k)/(omega) = (2pi//lambda)/(2 pi f) = (1)/(c)`.