Home
Class 12
PHYSICS
If the excess pressure inside a soap bub...

If the excess pressure inside a soap bubble of radius `r_(1)` in air is equal to the excess pressure inside air bubble of radius `r_(2)` inside the soap solution, then `r_(1):r_(2)` is

A

`2:1`

B

`1:2`

C

`1:4`

D

`sqrt(2):1`

Text Solution

Verified by Experts

The correct Answer is:
A
When the soap bubble of radius `r_(1)` in air, the excess pressure
`Deltap_(1)=(4T)/(r_(1))`
When the air bubble of radius `r_(2)` inside the soap solution, the excess pressure
`Deltap_(2)=(2T)/(r_(2))`
`therefore (Deltap_(1))/(Deltap_(2))=(4T)/(r_(1))/(2T)/(r_(2))`
`Deltap_(1) and Deltap_(2)` are same
`(Deltap_(1))/(Deltap_(2))=1`
`therefore 1=(2r_(2))/(r_(1))`
or `(r_(1))/(r_(2))=2`
or `r_(1):r_(2)=2:1`
Promotional Banner

Similar Questions

Explore conceptually related problems

Excess pressure inside a liquid drop is 60N/m^2 ?. What will be the excess pressure inside a liquid bubble of the same radius formed by the same liquid?

sum_(r=1)^(n) r.r ! is equal to

Obtain an expression for excess of pressure inside a drop of radius r and surface tension S.

Calculate the excess of pressure inside an air bubble of radius 1 mm formed just below the free surface of water.Given surface tension of water 72×10^(-3) Nm^(-1)

A soap bubble in air (two surfaces) has surface tension 0.03 Nm^(-1). Find the gauge pressure inside a bubble of diameter 30 mm.