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A partition wall has two layers of diffe...

A partition wall has two layers of different materials A and B in contact with each other. They have the same thickness but the thermal conductivity of layer A is twice that of layer B. At steady state if the temperature difference across the layer B is 50 K, then the corresponding difference across the layer A is

A

50 K

B

12.5 K

C

25 K

D

60 K

Text Solution

Verified by Experts

Suppose thickness of each wall is x then

`(K_(s)A(theta_(1)-theta_(2)))/(2x)=(2KA(theta_(1)-theta))/(x)`
Now, `K_(s)=(2xx2KxxK)/((2K+K))`
`=(4)/(3)K`
and `(theta_(1)-theta_(2))=50`
From Eq. (i)
`implies ((4)/(3)KAxx50)/(2x)=(2KA(theta_(1)-theta))/(x)`
or `(theta_(1)-theta)=16.6K`
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