The average total energy in one time period of a particle of mass m executing SHM of amplitude a and angular velocity `omega` is

Options

A. `(1)/(2)momega^(2)a^(2)`
B. `(1)/(4)momega^(2)a^(2)`
C. 0
D. `momega^(2)a^(2)`

Answer

A

Explanation

The average total energy
`E=(1)/(2)m omega^(2)a^(2)`
Total energy is not position function.