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The number of electrons per second flowi...

The number of electrons per second flowing through any cross-section of the wire carrying current of 1 A is

A

`3.12xx10^(16)`

B

`1.6xx10^(18)`

C

`6.25xx10^(16)`

D

`3.12xx10^(18)`

Text Solution

Verified by Experts

The correct Answer is:
C

Current `I=(q)/(t)`
`I=(q)/(1)`
`I=n e`
The number of electron
`n=(I)/(e)`
`=(1)/(1.6xx10^(-19))`
`=6.25xx10^(18)`
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