A magnet takes a minute to make 30 oscillations in a magnetic field. If the field strength is doubled, then the time period of oscillation (in sec) is

Options

A. `sqrt(2)`
B. `2sqrt(2)`
C. `(sqrt(3))/(2)`
D. `sqrt(3)`

Answer

A

Explanation

Time period of oscillation
`T=2pisqrt((I)/(MB_(H)))`
`therefore (T_(2)^(2))/(T_(1)^(2))=(B_(1))/(B_(2))`
`(T_(2)^(2))/((2)^(2))=(B)/(2B)`
`T_(2)^(2)=(4)/(2)`
`T_(2)=sqrt(2)s`