If alpha particle, proton and electron move with the same momentum, then their respective de-Broglie wavelengths `lambda_(alpha),lambda_(p),lambda_(e)` are related as

Options

A. `lambda_(alpha)=lambda_(p)=lambda_(e)`
B. `lambda_(alpha)ltlambda_(p)ltlambda_(e)`
C. `lambda_(alpha)gtlambda_(p)gtlambda_(e)`
D. `lambda_(p)gtlambda_(e)gtlambda_(alpha)`

Answer

A

Explanation

Wavelength `lambda=(h)/(p)`
Since, momentum is same for all the particles.
So, wavelength will be same for all
i.e., `lambda_(alpha)=lambda_(P)=lamda_(e)`