If the time period of oscillation of a pendulum is measured as 2.5 s using a stop watch with the leastcount `(1)/(2)s`, then the permissible error in the measurement is

Options

A. A)`10%`
B. `B) 30%`
C. `C) 15%`
D. `D) 20%`

Answer

D

Explanation

We have, `(Deltat)/(t)=(0.5)/(2.5)=(1)/(5)`
`(Deltat)/(t)%=(1)/(5)xx100=20%`