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The percentage error in measuring M, L a...

The percentage error in measuring M, L and T are 1 %, 1.5% and 3% respectively. Then the percentage error in measuring the physical quantity with dimensions `["ML"^(-1) "T"^(-1)]` is

A

a)0.01

B

`b) 3.5%`

C

c) 0.03

D

`D)5.5%`

Text Solution

Verified by Experts

The correct Answer is:
D
Given, percentage error in measuring M = 1%
Percentage error in measuring L = 1.5%
Percentage error in measuring T = 3%
Now the percentage error in measuring the physical quantity with dimensions `["ML"^(-1) "T"^(-1) ]` is
`(Delta x)/( x ) xx 100 = (DeltaM)/(M) xx 100 + (Delta L)/( L) xx 100`
`(Delta x)/( x) xx 100 = 1 + 1.5 + 3`
`(Delta x)/( x) xx 100 = 5.5%`
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