A constant force `F` acts on a particle of mass 1 kg moving with a velocity `v`, for one second. The distance moved in that time is

Options

A. 0
B. `(F)/(2)`
C. 2F
D. `v+ (F)/(2)`

Answer

D

Explanation

Given, m =1 kg and t = 1s
We know that, `F ="ma"`
`a= (F)/(m) = (F)/(1) = F`
From equation of motion,
`s= ut + (1)/(2) at^(2) = v + (1)/(2) F(1)^(2) = v + (F)/(2)`