The displacement of a particle in SHM is `x=10 sin (2t - (pi)/(6) )"m"`. When its displacement is 6 m, the velocity of the particle (in `"ms"^(-1)` ) is

Options

A. 8
B. 24
C. 16
D. 10

Answer

C

Explanation

Given, `x = 10 sin (2t - (pi)/(6))`
`x= 6m`
Here, `omega = 2 and A = 10`
We know that for SHM,
`v = omega sqrt(A^2 -x^2)`
`v=2 sqrt(10^2 - 6^2)`
`v= 2 xx 8`
`v = 16 "ms"^(-1)`