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If the electric flux entering and leavin...

If the electric flux entering and leaving a closed surface are `6 xx 10^(6) and 9 xx 10^(6)` SI units respectively, then the charge inside the surface of permittivity of free space `epsilon_(0)` is

A

`a)epsilon_(0) xx 10^6`

B

`b)-epsilon_(0) xx 10^6`

C

c)`-2 epsilon_(0) xx 10^6`

D

`d)3 epsilon_(0) xx 10^6`

Text Solution

Verified by Experts

The correct Answer is:
D
Net flux= leaving flux-entering flux
`phi= 9 xx 10^(6) - 6 xx 10^(6) = 3 xx 10^(6)`
Here, `phi = (q)/( epsilon_0)`
`q = phi epsilon_0 = 3xx 10^6 xx epsilon`
`q = 3 epsilon_0 xx 10^6`
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