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Three capacitors connected in series hav...

Three capacitors connected in series have an effective capacitance of `4 muF`. If one of the capacitance is removed, the net capacitance of the capacitor increases to `6mu F`. The removed capacitor has a capacitance of

A

`a)2 mu F`

B

`b)4 mu F`

C

c)`10 mu F`

D

d)`12 mu F`

Text Solution

Verified by Experts

The correct Answer is:
D
We knows when three capacitors connected in series
`(1)/( C) = (1)/( C_1) + (1) /( C_2) + (1)/(C_3)`
Here, `(1)/( C_1) + (1)/(C_2) + (1)/(C_3) = (1)/(4)`
Now, on removing one capacitor the resultant is
`(1)/(C_1) + (1)/(C_2) = (1)/(6)`
So, `(1)/(6) + (1)/( C_3) = (1)/(4)`
`(1)/(C_3) = (1)/(4) - (1)/(6) = (6-4)/(24) = (2)/(24) = (1)/(24)`
`C_3 = 12 muF`
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