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Resistance of 12 Omega and X Omega are c...

Resistance of `12 Omega and X Omega` are connected in parallel in the left gap and resistances of `9 Omega and 7 Omega` are connected in series in the right gap of the meter bridge. If the balancing length is 36 cm, then the value of resistance X is

A

`72 Omega`

B

`54 Omega`

C

`36 Omega`

D

`64 Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
In a balanced bridge,
`(R_1)/(R_2) = (i_1)/(i_2)`
On connected gap
`(12 X)/( (12+X)/(16)) = (36)/(64)`
`(12 X)/( (12 + X) 16) = (36)/(64)`
`(X)/( 12+ X) = (3)/(4)`
`rArr 4X = 36 + 3X`
`X= 36 Omega`
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