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In a potentiometer of wire length l, a c...

In a potentiometer of wire length `l`, a cell of emf V is balanced at a length `(l)/(3)` from the positive of the wire. For another cell of emf `1.5 V`, the balancing length becomes

A

`l/6`

B

`l/2`

C

`l/3`

D

`(2l)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
For balanced potentiometer,
`(E_1)/(E_2) = (l_1)/(l_2)`
Hence, `(V)/(1.5V) = (l//3)/( l_2)`
`(1)/(1.5) = (l)/(3l_2)`
`l_2 = (1.5)/(3) l`
`l_2 = (l)/(2)`
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