An AC source of voltage E = 20 sin 100t ...

An AC source of voltage `E = 20 sin 100t` is connected across a resistance `20 Omega`. The rms value of current in the circuit is

A

`1A`

B

`1/2 A`

C

`sqrt2`

D

`(1)/( sqrt2) A`

Verified by Experts

The correct Answer is:

D

Given, `E = 20 sin 100 t`
`E_0 = 20 Omega`
Here, `I_0 = (20)/( 20) = 1 A`
`I_("ms") = (I_0)/( sqrt2) = (1)/( sqrt2) A`

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