If the radius of the dees of cyclotron is r, then the kinetic energy of a proton of mass m accelerated by the cyclotron at an oscillating frequency v is

Options

A. `4pi ^(2) m ^(2) v ^(2) r ^(2)`
B. `4pi ^(2) mv ^(2) I ^(2)`
C. `2pi ^(2) mv ^(2) r ^(2)`
D. `pi ^(2) m v ^(2) l ^(2)`

Answer

C

Explanation

Given,
r=the outside radius of the dees
v=the speed of the particle when travelling in a path of this radius
m=the mass of proton
Kinetic energy of particles accelerated in a cyclotron
`K = 2pi ^(2) mv ^(2) r ^(2)`