The ratio of the surface area of the nuclei `""_(52) Te^(125)` to that of `""_(13) Al^(27)` is

Options

A. a)`5/3`
B. b)`(125)/(17)`
C. c)`1/4`
D. `d)(25)/(9)`

Answer

D

Explanation

By nuclear size
The radius of the nucleus
`R = R _(0) A ^( 1//3)`
whre , `R _(0) = 1.1 xx 10 ^(-15) m` is an empirical constant,
So, `R prop A ^(1//3) `
`R _(Te) = A _(Te) ^( 1//3)" "...(i)`
`R _(Al) = A _(Al) ^(1//3) " "...(ii)`
`(R _(Te))/(R _(Al)) = ((125)/(27)) ^(1//3) = (5)/(3)`
`therefore (A _(Te))/(A _(Al)) = ((5)/(3)) ^(2) = (25)/(9)`