In a simple pendulum experiment, the maximum percentage error in the measurement of length is 2% and that in the observation of the time period is 3%. Then, the maximum percentage error in determination of the acceleration due to gravity g is

Options

A. a)`5%`
B. b)` 6%`
C. c)` 7%`
D. d)`8%`

Answer

D

Explanation

The maximum percentage error
`(Delta g )/( g) = ( Delta l)/(l) + | (Delta T)/(T) | ^(2)`
`= (Delta l )/(l) +2 ( Delta T)/(T)` whre `(Delta l)/(l) = 2 $`
`(Delta g )/(g) = 2 % + 2 xx 3 % (Delta T)/(T) = 3 %`
`= 2 % + 6 % = 8%`