From the top of tower, a stone is thrown...

From the top of tower, a stone is thrown up. It reaches the ground in tq second. A second stone thrown down with the same speed reaches the ground in `t_1` second. A third stone released from rest reaches the ground in `t_2` second. Then

A

` t_3= ( (t_1+t_2))/(2)`

B

` t_3= sqrt(t_1t_2) `

C

` (1)/(t_3) =(1)/(t_1) - ( 1) /(t_2)`

D

` t_3^(2) =t_2^(2) -t_1^(2)`

Verified by Experts

The correct Answer is:

B

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