The currents `i_1 and i_2` through the resistors `R_1 (=10 Omega ) and R_2 (= 30 Omega ) ` in the circuit diagram with ` E_1 = 3V, E_2= 3V and E_3 = 2 V ` are respectively :
` (##ARH_15Y_KRL_CEE_SP_05_E01_063_Q01.png" width="80%">

Options

A. ` 0.2 A , 0.1 A `
B. ` 0.4 A, 0.2 A `
C. ` 0.1 A , 0.2 A `
D. ` 0.2 A , 0.4 A `

Answer

A

Explanation

In closed loop EFGDE

` " " i_2R_2= E_2`
` " " i_2 xx 30 = 3`
` " "i_2 =0.1 A `
In closed loop ABCEA
`- i_1 R_1- E_1+ E_2 +E_3 = 0`
` " " - i_1 xx 10- 3 + 3 + 2=0`
` " " i_1= 0.2 A `