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An alpha - particle with a specific ch...

An ` alpha - ` particle with a specific charge of `2.5 xx 10 ^(7) C kg ^(-1) ` moves with a speed of ` 2xx 10 ^(5) ms^(-1) ` in a perpendicular magnetic field of 0.05 T. Then the radius of the circular path described by it is :

A

8 cm

B

4 cm

C

16 cm

D

2 cm

Text Solution

Verified by Experts

The correct Answer is:
C
` " " r = (mv)/(Bq)`
` rArr " " r= ( v)/(B (q)/(m)) = (2xx 10^(5))/(0.-05 xx 2.5 xx 10^(7)) `
` ( 2xx 10 ^(7))/( 12.5 xx 10^(7)) = (200)/(12.5) cm = 16 cm `
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