The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. If the escape velocity from the earth is v, then the escape velocity from the planet is :

Options

A. `sqrt(3)v`
B. `sqrt(2)v`
C. v
D. `sqrt(5)v`

Answer

A

Explanation

Escape velocity, `v_(e)=sqrt((2GM_(e))/R_(e))`
Given, `" "M_(p)=6M_(e), R_(p)=2R_(e)`
`therefore" "v_(p)=sqrt((2G6M_(e))/((2R_(e))))=sqrt(3)v_(e)`