In a gas, two waves of wavelengths 1 m and 1.01 m are superposed and produce 10 beats in 3 s. The velocity of sound in the medium is :

Options

A. 300 m/s
B. 336.7 m/s
C. 360.2 m/s
D. 270 m/s

Answer

B

Explanation

The velocity (v) is given by
`" "v=flambda`
`rArr" "f=v/lambda`
Number of beats = difference in frequencies
`therefore f_(1)-f_(2)=v(1/lambda_(1)-1/lambda_(2))`
`" "10/3=v(1/1-1/(1.01))`
`" "10/3=v((0.01)/(1.01))`
`rArr" "v=(10 times 1.01)/(3 times 0.01)=336.7m//s`