The pressure inside two soap bubbles is 1.01 and 1.02 atmosphere respectively. The ratio of their respective volume is :

Options

A. 2
B. 4
C. 6
D. 8

Answer

A

Explanation

Excess pressure is given by `P=(4T)/r`
`rArr" "r=(4T)/P`
`therefore" "r_(1)/r_(2)=P_(2)/P_(1)=(1.02)/(1.01)=101/101`
Ratio of volume.s =`(4/3pir_(1)""^(3))/(4/3pir_(2)""^(3))=(102)^(3)/(101)^(3) approx 2`