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A varying magnetic flux linking a coil i...

A varying magnetic flux linking a coil is given by `phi=Xt^(2)`. If a time t = 3s, the emf induced is 9 V, then the value of X is :

A

0.66 Wb `s^(-2)`

B

1.5 Wb `s^(-2)`

C

`-0.66" Wb "s^(-2)`

D

`-1.5" Wb "s^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
From Faraday.s law, induced emf is
`" "e=-(dphi)/(dt)`
Given, `" "phi=Xt^(2)`
`therefore" "e=(-d(Xt^(2)))/(dt)=-2tX`
Given, `" "t=3, e=9V`
`therefore" "X=9/(3 times 2)=1.5 Wb" "s^(-2)`
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