A silicon specimen is made into a p-type semiconductor by doping, on an average, one indium atom per `5 times 10^(7)` silicon atoms. If the number density of atoms in the silicon specimen is `5 times 10^(28)` atom/`m^(3)`, then the number of acceptor atoms in silicon per cubic centimetre will be :

Options

A. `2.5 times 10^(30)` atom/`cm^(3)`
B. `2.5 times 10^(35)` atom/`cm^(3)`
C. `1 times 10^(13)" atom"//cm^(3)`
D. `1 times 10^(15)" atom"//cm^(3)`

Answer

D

Explanation

Number density of atoms in silicon specimen `=5 times 10^(28)"atoms"//m^(3)=5 times 10^(22)"atoms"//cm^(3)`.
Since, 1 atom of indium is doped in `5 times 10^(7)` silicon atoms, so total number of indium atoms doped per `cm^(3)` of silicon will be
`" "n=(5 times 10^(22))/(5 times 10^(7))=10^(15)"atoms"//cm^(3)`