A 2 kg copper block is heated to `500^(@)C` and then it is placed on a large block of ice at `0^(@)C`. If the specific heat capacity of copper is `400" J "kg^(-1)""^(@)C^(-1)` and latent heat of fusion of watter is `3.5 times 10^(5)" J "kg^(-1)`, the amount of ice that can melt is :

Options

A. 7/8 kg
B. 7/5 kg
C. 8/7 kg
D. 5/7 kg

Answer

C

Explanation

Heat emitted by copper = Heat gained by ice
`" "mcDeltatheta=m.L`
`rArr" "m^(.)=(mcDeltatheta)/L`
Given, m = 2kg, c = 400 J `Kg^(-1)C^(-1)`,
`" "Deltatheta=500, L=3.5 times 10^(5)" J "kg^(-1)`
`therefore" "m.=(2 times 400 times 500)/(3.5 times 10^(5))=8/7kg`