In a common-emitter amplifier, the load resistance of the output circuit is 1000 times the resistance of the input circuit. If `alpha=0.98`, then voltage gain is :

Options

A. `49 times 10^(3)`
B. `2.5 times 10^(2)`
C. `1.5 times 10^(2)`
D. `4.9`

Answer

A

Explanation

Given,
`" "beta=alpha/(1-alpha)=(0.98)/(1-0.98)=49`
`therefore" Voltage again"=beta""R_(2)/R_(1)=49 times 1000=49 times 10^(3)`